7(y-2)+13=3(y+5)

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Solution for 7(y-2)+13=3(y+5) equation: 



7(y-2)+13=3(y+5)

We move all terms to the left:

7(y-2)+13-(3(y+5))=0

We multiply parentheses

7y-(3(y+5))-14+13=0



We calculate terms in parentheses: -(3(y+5)), so:

3(y+5)

We multiply parentheses

3y+15

Back to the equation:

-(3y+15)



We add all the numbers together, and all the variables

7y-(3y+15)-1=0

We get rid of parentheses

7y-3y-15-1=0

We add all the numbers together, and all the variables

4y-16=0

We move all terms containing y to the left, all other terms to the right

4y=16

y=16/4

y=4

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