7(y-2)+2y=-3(y+4)-2y

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Solution for 7(y-2)+2y=-3(y+4)-2y equation: 



7(y-2)+2y=-3(y+4)-2y

We move all terms to the left:

7(y-2)+2y-(-3(y+4)-2y)=0

We add all the numbers together, and all the variables

2y+7(y-2)-(-3(y+4)-2y)=0

We multiply parentheses

2y+7y-(-3(y+4)-2y)-14=0



We calculate terms in parentheses: -(-3(y+4)-2y), so:

-3(y+4)-2y

We add all the numbers together, and all the variables

-2y-3(y+4)

We multiply parentheses

-2y-3y-12

We add all the numbers together, and all the variables

-5y-12

Back to the equation:

-(-5y-12)



We add all the numbers together, and all the variables

9y-(-5y-12)-14=0

We get rid of parentheses

9y+5y+12-14=0

We add all the numbers together, and all the variables

14y-2=0

We move all terms containing y to the left, all other terms to the right

14y=2

y=2/14

y=1/7

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