7(y-3)-2=3(2y-5)+4

Solution for 7(y-3)-2=3(2y-5)+4 equation:

Simplifying
7(y + -3) + -2 = 3(2y + -5) + 4

Reorder the terms:
7(-3 + y) + -2 = 3(2y + -5) + 4
(-3 * 7 + y * 7) + -2 = 3(2y + -5) + 4
(-21 + 7y) + -2 = 3(2y + -5) + 4

Reorder the terms:
-21 + -2 + 7y = 3(2y + -5) + 4

Combine like terms: -21 + -2 = -23
-23 + 7y = 3(2y + -5) + 4

Reorder the terms:
-23 + 7y = 3(-5 + 2y) + 4
-23 + 7y = (-5 * 3 + 2y * 3) + 4
-23 + 7y = (-15 + 6y) + 4

Reorder the terms:
-23 + 7y = -15 + 4 + 6y

Combine like terms: -15 + 4 = -11
-23 + 7y = -11 + 6y

Solving
-23 + 7y = -11 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
-23 + 7y + -6y = -11 + 6y + -6y

Combine like terms: 7y + -6y = 1y
-23 + 1y = -11 + 6y + -6y

Combine like terms: 6y + -6y = 0
-23 + 1y = -11 + 0
-23 + 1y = -11

Add '23' to each side of the equation.
-23 + 23 + 1y = -11 + 23

Combine like terms: -23 + 23 = 0
0 + 1y = -11 + 23
1y = -11 + 23

Combine like terms: -11 + 23 = 12
1y = 12

Divide each side by '1'.
y = 12

Simplifying
y = 12