7(y-3)-4(y+1)=-5(y+5)

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Solution for 7(y-3)-4(y+1)=-5(y+5) equation: 



7(y-3)-4(y+1)=-5(y+5)

We move all terms to the left:

7(y-3)-4(y+1)-(-5(y+5))=0

We multiply parentheses

7y-4y-(-5(y+5))-21-4=0



We calculate terms in parentheses: -(-5(y+5)), so:

-5(y+5)

We multiply parentheses

-5y-25

Back to the equation:

-(-5y-25)



We add all the numbers together, and all the variables

3y-(-5y-25)-25=0

We get rid of parentheses

3y+5y+25-25=0

We add all the numbers together, and all the variables

8y=0

y=0/8

y=0

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