7(y-3)-5=-6(-3y+3)-y

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Solution for 7(y-3)-5=-6(-3y+3)-y equation: 



7(y-3)-5=-6(-3y+3)-y

We move all terms to the left:

7(y-3)-5-(-6(-3y+3)-y)=0

We multiply parentheses

7y-(-6(-3y+3)-y)-21-5=0



We calculate terms in parentheses: -(-6(-3y+3)-y), so:

-6(-3y+3)-y

We add all the numbers together, and all the variables

-1y-6(-3y+3)

We multiply parentheses

-1y+18y-18

We add all the numbers together, and all the variables

17y-18

Back to the equation:

-(17y-18)



We add all the numbers together, and all the variables

7y-(17y-18)-26=0

We get rid of parentheses

7y-17y+18-26=0

We add all the numbers together, and all the variables

-10y-8=0

We move all terms containing y to the left, all other terms to the right

-10y=8

y=8/-10

y=-4/5

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