7(y-3)=2(3y+4)-29

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Solution for 7(y-3)=2(3y+4)-29 equation:


Simplifying
7(y + -3) = 2(3y + 4) + -29

Reorder the terms:
7(-3 + y) = 2(3y + 4) + -29
(-3 * 7 + y * 7) = 2(3y + 4) + -29
(-21 + 7y) = 2(3y + 4) + -29

Reorder the terms:
-21 + 7y = 2(4 + 3y) + -29
-21 + 7y = (4 * 2 + 3y * 2) + -29
-21 + 7y = (8 + 6y) + -29

Reorder the terms:
-21 + 7y = 8 + -29 + 6y

Combine like terms: 8 + -29 = -21
-21 + 7y = -21 + 6y

Add '21' to each side of the equation.
-21 + 21 + 7y = -21 + 21 + 6y

Combine like terms: -21 + 21 = 0
0 + 7y = -21 + 21 + 6y
7y = -21 + 21 + 6y

Combine like terms: -21 + 21 = 0
7y = 0 + 6y
7y = 6y

Solving
7y = 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
7y + -6y = 6y + -6y

Combine like terms: 7y + -6y = 1y
1y = 6y + -6y

Combine like terms: 6y + -6y = 0
1y = 0

Divide each side by '1'.
y = 0

Simplifying
y = 0

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