7(y-3)=2(y-9)+2y

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Solution for 7(y-3)=2(y-9)+2y equation: 



7(y-3)=2(y-9)+2y

We move all terms to the left:

7(y-3)-(2(y-9)+2y)=0

We multiply parentheses

7y-(2(y-9)+2y)-21=0



We calculate terms in parentheses: -(2(y-9)+2y), so:

2(y-9)+2y

We add all the numbers together, and all the variables

2y+2(y-9)

We multiply parentheses

2y+2y-18

We add all the numbers together, and all the variables

4y-18

Back to the equation:

-(4y-18)



We get rid of parentheses

7y-4y+18-21=0

We add all the numbers together, and all the variables

3y-3=0

We move all terms containing y to the left, all other terms to the right

3y=3

y=3/3

y=1

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