7(y-4)+1=-2(y-18)

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Solution for 7(y-4)+1=-2(y-18) equation: 



7(y-4)+1=-2(y-18)

We move all terms to the left:

7(y-4)+1-(-2(y-18))=0

We multiply parentheses

7y-(-2(y-18))-28+1=0



We calculate terms in parentheses: -(-2(y-18)), so:

-2(y-18)

We multiply parentheses

-2y+36

Back to the equation:

-(-2y+36)



We add all the numbers together, and all the variables

7y-(-2y+36)-27=0

We get rid of parentheses

7y+2y-36-27=0

We add all the numbers together, and all the variables

9y-63=0

We move all terms containing y to the left, all other terms to the right

9y=63

y=63/9

y=7

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