7(y-4)+29=7y-1-(2-y)

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Solution for 7(y-4)+29=7y-1-(2-y) equation: 



7(y-4)+29=7y-1-(2-y)

We move all terms to the left:

7(y-4)+29-(7y-1-(2-y))=0

We add all the numbers together, and all the variables

7(y-4)-(7y-1-(-1y+2))+29=0

We multiply parentheses

7y-(7y-1-(-1y+2))-28+29=0



We calculate terms in parentheses: -(7y-1-(-1y+2)), so:

7y-1-(-1y+2)

determiningTheFunctionDomain
7y-(-1y+2)-1

We get rid of parentheses

7y+1y-2-1

We add all the numbers together, and all the variables

8y-3

Back to the equation:

-(8y-3)



We add all the numbers together, and all the variables

7y-(8y-3)+1=0

We get rid of parentheses

7y-8y+3+1=0

We add all the numbers together, and all the variables

-1y+4=0

We move all terms containing y to the left, all other terms to the right

-y=-4

y=-4/-1

y=+4

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