7(y-4)+3(y+1)=35

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Solution for 7(y-4)+3(y+1)=35 equation: 


Simplifying
7(y + -4) + 3(y + 1) = 35

Reorder the terms:
7(-4 + y) + 3(y + 1) = 35
(-4 * 7 + y * 7) + 3(y + 1) = 35
(-28 + 7y) + 3(y + 1) = 35

Reorder the terms:
-28 + 7y + 3(1 + y) = 35
-28 + 7y + (1 * 3 + y * 3) = 35
-28 + 7y + (3 + 3y) = 35

Reorder the terms:
-28 + 3 + 7y + 3y = 35

Combine like terms: -28 + 3 = -25
-25 + 7y + 3y = 35

Combine like terms: 7y + 3y = 10y
-25 + 10y = 35

Solving
-25 + 10y = 35

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 10y = 35 + 25

Combine like terms: -25 + 25 = 0
0 + 10y = 35 + 25
10y = 35 + 25

Combine like terms: 35 + 25 = 60
10y = 60

Divide each side by '10'.
y = 6

Simplifying
y = 6

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