7(y-4)+8y=5(3y+4)-8

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Solution for 7(y-4)+8y=5(3y+4)-8 equation:


Simplifying
7(y + -4) + 8y = 5(3y + 4) + -8

Reorder the terms:
7(-4 + y) + 8y = 5(3y + 4) + -8
(-4 * 7 + y * 7) + 8y = 5(3y + 4) + -8
(-28 + 7y) + 8y = 5(3y + 4) + -8

Combine like terms: 7y + 8y = 15y
-28 + 15y = 5(3y + 4) + -8

Reorder the terms:
-28 + 15y = 5(4 + 3y) + -8
-28 + 15y = (4 * 5 + 3y * 5) + -8
-28 + 15y = (20 + 15y) + -8

Reorder the terms:
-28 + 15y = 20 + -8 + 15y

Combine like terms: 20 + -8 = 12
-28 + 15y = 12 + 15y

Add '-15y' to each side of the equation.
-28 + 15y + -15y = 12 + 15y + -15y

Combine like terms: 15y + -15y = 0
-28 + 0 = 12 + 15y + -15y
-28 = 12 + 15y + -15y

Combine like terms: 15y + -15y = 0
-28 = 12 + 0
-28 = 12

Solving
-28 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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