7(y-4)-2(y+7)=7-2(4y-5)

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Solution for 7(y-4)-2(y+7)=7-2(4y-5) equation: 



7(y-4)-2(y+7)=7-2(4y-5)

We move all terms to the left:

7(y-4)-2(y+7)-(7-2(4y-5))=0

We multiply parentheses

7y-2y-(7-2(4y-5))-28-14=0



We calculate terms in parentheses: -(7-2(4y-5)), so:

7-2(4y-5)

determiningTheFunctionDomain
-2(4y-5)+7

We multiply parentheses

-8y+10+7

We add all the numbers together, and all the variables

-8y+17

Back to the equation:

-(-8y+17)



We add all the numbers together, and all the variables

5y-(-8y+17)-42=0

We get rid of parentheses

5y+8y-17-42=0

We add all the numbers together, and all the variables

13y-59=0

We move all terms containing y to the left, all other terms to the right

13y=59

y=59/13

y=4+7/13

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