7(y-4)=-3(y-2)

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Solution for 7(y-4)=-3(y-2) equation: 



7(y-4)=-3(y-2)

We move all terms to the left:

7(y-4)-(-3(y-2))=0

We multiply parentheses

7y-(-3(y-2))-28=0



We calculate terms in parentheses: -(-3(y-2)), so:

-3(y-2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)



We get rid of parentheses

7y+3y-6-28=0

We add all the numbers together, and all the variables

10y-34=0

We move all terms containing y to the left, all other terms to the right

10y=34

y=34/10

y=3+2/5

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