7(y-4)=6(y-2)

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Solution for 7(y-4)=6(y-2) equation:


Simplifying
7(y + -4) = 6(y + -2)

Reorder the terms:
7(-4 + y) = 6(y + -2)
(-4 * 7 + y * 7) = 6(y + -2)
(-28 + 7y) = 6(y + -2)

Reorder the terms:
-28 + 7y = 6(-2 + y)
-28 + 7y = (-2 * 6 + y * 6)
-28 + 7y = (-12 + 6y)

Solving
-28 + 7y = -12 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
-28 + 7y + -6y = -12 + 6y + -6y

Combine like terms: 7y + -6y = 1y
-28 + 1y = -12 + 6y + -6y

Combine like terms: 6y + -6y = 0
-28 + 1y = -12 + 0
-28 + 1y = -12

Add '28' to each side of the equation.
-28 + 28 + 1y = -12 + 28

Combine like terms: -28 + 28 = 0
0 + 1y = -12 + 28
1y = -12 + 28

Combine like terms: -12 + 28 = 16
1y = 16

Divide each side by '1'.
y = 16

Simplifying
y = 16

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