7(y-5)/3=2y

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Solution for 7(y-5)/3=2y equation: 



7(y-5)/3=2y

We move all terms to the left:

7(y-5)/3-(2y)=0

We add all the numbers together, and all the variables

-2y+7(y-5)/3=0

We multiply all the terms by the denominator


-2y*3+7(y-5)=0

We multiply parentheses

-2y*3+7y-35=0

Wy multiply elements

-6y+7y-35=0

We add all the numbers together, and all the variables

y-35=0

We move all terms containing y to the left, all other terms to the right

y=35

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