7(y-5)=-3(2+y)

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Solution for 7(y-5)=-3(2+y) equation: 



7(y-5)=-3(2+y)

We move all terms to the left:

7(y-5)-(-3(2+y))=0

We add all the numbers together, and all the variables

7(y-5)-(-3(y+2))=0

We multiply parentheses

7y-(-3(y+2))-35=0



We calculate terms in parentheses: -(-3(y+2)), so:

-3(y+2)

We multiply parentheses

-3y-6

Back to the equation:

-(-3y-6)



We get rid of parentheses

7y+3y+6-35=0

We add all the numbers together, and all the variables

10y-29=0

We move all terms containing y to the left, all other terms to the right

10y=29

y=29/10

y=2+9/10

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