7(y-6)-3=-3(6y+9)-y

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Solution for 7(y-6)-3=-3(6y+9)-y equation: 



7(y-6)-3=-3(6y+9)-y

We move all terms to the left:

7(y-6)-3-(-3(6y+9)-y)=0

We multiply parentheses

7y-(-3(6y+9)-y)-42-3=0



We calculate terms in parentheses: -(-3(6y+9)-y), so:

-3(6y+9)-y

We add all the numbers together, and all the variables

-1y-3(6y+9)

We multiply parentheses

-1y-18y-27

We add all the numbers together, and all the variables

-19y-27

Back to the equation:

-(-19y-27)



We add all the numbers together, and all the variables

7y-(-19y-27)-45=0

We get rid of parentheses

7y+19y+27-45=0

We add all the numbers together, and all the variables

26y-18=0

We move all terms containing y to the left, all other terms to the right

26y=18

y=18/26

y=9/13

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