7(y-8)+24=13/9(y-6)

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Solution for 7(y-8)+24=13/9(y-6) equation:



7(y-8)+24=13/9(y-6)
We move all terms to the left:
7(y-8)+24-(13/9(y-6))=0
Domain of the equation: 9(y-6))!=0
y∈R
We multiply parentheses
7y-(13/9(y-6))-56+24=0
We multiply all the terms by the denominator
7y*9(y-6))-(13-56*9(y-6))+24*9(y-6))=0
We add all the numbers together, and all the variables
7y*9(y-6))-(13-56*9(y-6))+24*9(y=0
Wy multiply elements
63y^2(y-4536y^2(y=0

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