7(y-8)+27=-3(y-6)

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Solution for 7(y-8)+27=-3(y-6) equation: 



7(y-8)+27=-3(y-6)

We move all terms to the left:

7(y-8)+27-(-3(y-6))=0

We multiply parentheses

7y-(-3(y-6))-56+27=0



We calculate terms in parentheses: -(-3(y-6)), so:

-3(y-6)

We multiply parentheses

-3y+18

Back to the equation:

-(-3y+18)



We add all the numbers together, and all the variables

7y-(-3y+18)-29=0

We get rid of parentheses

7y+3y-18-29=0

We add all the numbers together, and all the variables

10y-47=0

We move all terms containing y to the left, all other terms to the right

10y=47

y=47/10

y=4+7/10

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