7(y-8)=24+-3(y-6)

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Solution for 7(y-8)=24+-3(y-6) equation: 



7(y-8)=24+-3(y-6)

We move all terms to the left:

7(y-8)-(24+-3(y-6))=0

We use the square of the difference formula

7(y-8)-(24-3(y-6))=0

We multiply parentheses

7y-(24-3(y-6))-56=0



We calculate terms in parentheses: -(24-3(y-6)), so:

24-3(y-6)

determiningTheFunctionDomain
-3(y-6)+24

We multiply parentheses

-3y+18+24

We add all the numbers together, and all the variables

-3y+42

Back to the equation:

-(-3y+42)



We get rid of parentheses

7y+3y-42-56=0

We add all the numbers together, and all the variables

10y-98=0

We move all terms containing y to the left, all other terms to the right

10y=98

y=98/10

y=9+4/5

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