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7(z+1)-2(z-1)=2z-2+2z-3
We move all terms to the left:
7(z+1)-2(z-1)-(2z-2+2z-3)=0
We add all the numbers together, and all the variables
7(z+1)-2(z-1)-(4z-5)=0
We multiply parentheses
7z-2z-(4z-5)+7+2=0
We get rid of parentheses
7z-2z-4z+5+7+2=0
We add all the numbers together, and all the variables
z+14=0
We move all terms containing z to the left, all other terms to the right
z=-14
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