7(z+1)=35

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Solution for 7(z+1)=35 equation:



7(z+1)=35
We move all terms to the left:
7(z+1)-(35)=0
We multiply parentheses
7z+7-35=0
We add all the numbers together, and all the variables
7z-28=0
We move all terms containing z to the left, all other terms to the right
7z=28
z=28/7
z=4

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