7(z+2)=2+4z

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Solution for 7(z+2)=2+4z equation: 



7(z+2)=2+4z

We move all terms to the left:

7(z+2)-(2+4z)=0

We add all the numbers together, and all the variables

7(z+2)-(4z+2)=0

We multiply parentheses

7z-(4z+2)+14=0

We get rid of parentheses

7z-4z-2+14=0

We add all the numbers together, and all the variables

3z+12=0

We move all terms containing z to the left, all other terms to the right

3z=-12

z=-12/3

z=-4

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