7(z+2)=3(z+1)-13

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Solution for 7(z+2)=3(z+1)-13 equation:


Simplifying
7(z + 2) = 3(z + 1) + -13

Reorder the terms:
7(2 + z) = 3(z + 1) + -13
(2 * 7 + z * 7) = 3(z + 1) + -13
(14 + 7z) = 3(z + 1) + -13

Reorder the terms:
14 + 7z = 3(1 + z) + -13
14 + 7z = (1 * 3 + z * 3) + -13
14 + 7z = (3 + 3z) + -13

Reorder the terms:
14 + 7z = 3 + -13 + 3z

Combine like terms: 3 + -13 = -10
14 + 7z = -10 + 3z

Solving
14 + 7z = -10 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
14 + 7z + -3z = -10 + 3z + -3z

Combine like terms: 7z + -3z = 4z
14 + 4z = -10 + 3z + -3z

Combine like terms: 3z + -3z = 0
14 + 4z = -10 + 0
14 + 4z = -10

Add '-14' to each side of the equation.
14 + -14 + 4z = -10 + -14

Combine like terms: 14 + -14 = 0
0 + 4z = -10 + -14
4z = -10 + -14

Combine like terms: -10 + -14 = -24
4z = -24

Divide each side by '4'.
z = -6

Simplifying
z = -6

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