7(z+2)=4(z+1)-11

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Solution for 7(z+2)=4(z+1)-11 equation: 



7(z+2)=4(z+1)-11

We move all terms to the left:

7(z+2)-(4(z+1)-11)=0

We multiply parentheses

7z-(4(z+1)-11)+14=0



We calculate terms in parentheses: -(4(z+1)-11), so:

4(z+1)-11

We multiply parentheses

4z+4-11

We add all the numbers together, and all the variables

4z-7

Back to the equation:

-(4z-7)



We get rid of parentheses

7z-4z+7+14=0

We add all the numbers together, and all the variables

3z+21=0

We move all terms containing z to the left, all other terms to the right

3z=-21

z=-21/3

z=-7

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