7(z+2)=4(z+1)-8

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Solution for 7(z+2)=4(z+1)-8 equation:


7(z+2)=4(z+1)-8

We simplify the equation to the form, which is simple to understand 
7(z+2)=4(z+1)-8

Reorder the terms in parentheses
+(+7z+14)=4*(z+1)-8

Remove unnecessary parentheses
+7z+14=+4+*(+z+1+)-8

Reorder the terms in parentheses
+7z+14=+(+4z+4)-8

Remove unnecessary parentheses
+7z+14=+4z+4-8

We move all terms containing z to the left and all other terms to the right. 
+7z-4z=+4-8-14

We simplify left and right side of the equation. 
+3z=-18

We divide both sides of the equation by 3 to get z. 
z=-6

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