7(z+2)=46+3z

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Solution for 7(z+2)=46+3z equation:



7(z+2)=46+3z
We move all terms to the left:
7(z+2)-(46+3z)=0
We add all the numbers together, and all the variables
7(z+2)-(3z+46)=0
We multiply parentheses
7z-(3z+46)+14=0
We get rid of parentheses
7z-3z-46+14=0
We add all the numbers together, and all the variables
4z-32=0
We move all terms containing z to the left, all other terms to the right
4z=32
z=32/4
z=8

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