7(z+2)=5(z+1)-9

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Solution for 7(z+2)=5(z+1)-9 equation:


Simplifying
7(z + 2) = 5(z + 1) + -9

Reorder the terms:
7(2 + z) = 5(z + 1) + -9
(2 * 7 + z * 7) = 5(z + 1) + -9
(14 + 7z) = 5(z + 1) + -9

Reorder the terms:
14 + 7z = 5(1 + z) + -9
14 + 7z = (1 * 5 + z * 5) + -9
14 + 7z = (5 + 5z) + -9

Reorder the terms:
14 + 7z = 5 + -9 + 5z

Combine like terms: 5 + -9 = -4
14 + 7z = -4 + 5z

Solving
14 + 7z = -4 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
14 + 7z + -5z = -4 + 5z + -5z

Combine like terms: 7z + -5z = 2z
14 + 2z = -4 + 5z + -5z

Combine like terms: 5z + -5z = 0
14 + 2z = -4 + 0
14 + 2z = -4

Add '-14' to each side of the equation.
14 + -14 + 2z = -4 + -14

Combine like terms: 14 + -14 = 0
0 + 2z = -4 + -14
2z = -4 + -14

Combine like terms: -4 + -14 = -18
2z = -18

Divide each side by '2'.
z = -9

Simplifying
z = -9

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