7(z+2)=7+7z+6-z

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Solution for 7(z+2)=7+7z+6-z equation: 



7(z+2)=7+7z+6-z

We move all terms to the left:

7(z+2)-(7+7z+6-z)=0

We add all the numbers together, and all the variables

7(z+2)-(6z+13)=0

We multiply parentheses

7z-(6z+13)+14=0

We get rid of parentheses

7z-6z-13+14=0

We add all the numbers together, and all the variables

z+1=0

We move all terms containing z to the left, all other terms to the right

z=-1

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