7(z+3)=29+3z

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Solution for 7(z+3)=29+3z equation: 



7(z+3)=29+3z

We move all terms to the left:

7(z+3)-(29+3z)=0

We add all the numbers together, and all the variables

7(z+3)-(3z+29)=0

We multiply parentheses

7z-(3z+29)+21=0

We get rid of parentheses

7z-3z-29+21=0

We add all the numbers together, and all the variables

4z-8=0

We move all terms containing z to the left, all other terms to the right

4z=8

z=8/4

z=2

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