7(z+3)=69+3z

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Solution for 7(z+3)=69+3z equation: 



7(z+3)=69+3z

We move all terms to the left:

7(z+3)-(69+3z)=0

We add all the numbers together, and all the variables

7(z+3)-(3z+69)=0

We multiply parentheses

7z-(3z+69)+21=0

We get rid of parentheses

7z-3z-69+21=0

We add all the numbers together, and all the variables

4z-48=0

We move all terms containing z to the left, all other terms to the right

4z=48

z=48/4

z=12

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