7(z+4)-(7+2z)=4z

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Solution for 7(z+4)-(7+2z)=4z equation:


Simplifying
7(z + 4) + -1(7 + 2z) = 4z

Reorder the terms:
7(4 + z) + -1(7 + 2z) = 4z
(4 * 7 + z * 7) + -1(7 + 2z) = 4z
(28 + 7z) + -1(7 + 2z) = 4z
28 + 7z + (7 * -1 + 2z * -1) = 4z
28 + 7z + (-7 + -2z) = 4z

Reorder the terms:
28 + -7 + 7z + -2z = 4z

Combine like terms: 28 + -7 = 21
21 + 7z + -2z = 4z

Combine like terms: 7z + -2z = 5z
21 + 5z = 4z

Solving
21 + 5z = 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
21 + 5z + -4z = 4z + -4z

Combine like terms: 5z + -4z = 1z
21 + 1z = 4z + -4z

Combine like terms: 4z + -4z = 0
21 + 1z = 0

Add '-21' to each side of the equation.
21 + -21 + 1z = 0 + -21

Combine like terms: 21 + -21 = 0
0 + 1z = 0 + -21
1z = 0 + -21

Combine like terms: 0 + -21 = -21
1z = -21

Divide each side by '1'.
z = -21

Simplifying
z = -21

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