7(z+4)=6(z-3)+z

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Solution for 7(z+4)=6(z-3)+z equation:


Simplifying
7(z + 4) = 6(z + -3) + z

Reorder the terms:
7(4 + z) = 6(z + -3) + z
(4 * 7 + z * 7) = 6(z + -3) + z
(28 + 7z) = 6(z + -3) + z

Reorder the terms:
28 + 7z = 6(-3 + z) + z
28 + 7z = (-3 * 6 + z * 6) + z
28 + 7z = (-18 + 6z) + z

Combine like terms: 6z + z = 7z
28 + 7z = -18 + 7z

Add '-7z' to each side of the equation.
28 + 7z + -7z = -18 + 7z + -7z

Combine like terms: 7z + -7z = 0
28 + 0 = -18 + 7z + -7z
28 = -18 + 7z + -7z

Combine like terms: 7z + -7z = 0
28 = -18 + 0
28 = -18

Solving
28 = -18

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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