7(z+4)=7(z-2)

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Solution for 7(z+4)=7(z-2) equation:


Simplifying
7(z + 4) = 7(z + -2)

Reorder the terms:
7(4 + z) = 7(z + -2)
(4 * 7 + z * 7) = 7(z + -2)
(28 + 7z) = 7(z + -2)

Reorder the terms:
28 + 7z = 7(-2 + z)
28 + 7z = (-2 * 7 + z * 7)
28 + 7z = (-14 + 7z)

Add '-7z' to each side of the equation.
28 + 7z + -7z = -14 + 7z + -7z

Combine like terms: 7z + -7z = 0
28 + 0 = -14 + 7z + -7z
28 = -14 + 7z + -7z

Combine like terms: 7z + -7z = 0
28 = -14 + 0
28 = -14

Solving
28 = -14

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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