7(z+7)-(1+3z)=3z

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Solution for 7(z+7)-(1+3z)=3z equation:


Simplifying
7(z + 7) + -1(1 + 3z) = 3z

Reorder the terms:
7(7 + z) + -1(1 + 3z) = 3z
(7 * 7 + z * 7) + -1(1 + 3z) = 3z
(49 + 7z) + -1(1 + 3z) = 3z
49 + 7z + (1 * -1 + 3z * -1) = 3z
49 + 7z + (-1 + -3z) = 3z

Reorder the terms:
49 + -1 + 7z + -3z = 3z

Combine like terms: 49 + -1 = 48
48 + 7z + -3z = 3z

Combine like terms: 7z + -3z = 4z
48 + 4z = 3z

Solving
48 + 4z = 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
48 + 4z + -3z = 3z + -3z

Combine like terms: 4z + -3z = 1z
48 + 1z = 3z + -3z

Combine like terms: 3z + -3z = 0
48 + 1z = 0

Add '-48' to each side of the equation.
48 + -48 + 1z = 0 + -48

Combine like terms: 48 + -48 = 0
0 + 1z = 0 + -48
1z = 0 + -48

Combine like terms: 0 + -48 = -48
1z = -48

Divide each side by '1'.
z = -48

Simplifying
z = -48

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