7(z+8)-(3z-9)=3z

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Solution for 7(z+8)-(3z-9)=3z equation: 



7(z+8)-(3z-9)=3z

We move all terms to the left:

7(z+8)-(3z-9)-(3z)=0

We add all the numbers together, and all the variables

-3z+7(z+8)-(3z-9)=0

We multiply parentheses

-3z+7z-(3z-9)+56=0

We get rid of parentheses

-3z+7z-3z+9+56=0

We add all the numbers together, and all the variables

z+65=0

We move all terms containing z to the left, all other terms to the right

z=-65

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