7(z+9)=27+3z

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Solution for 7(z+9)=27+3z equation: 



7(z+9)=27+3z

We move all terms to the left:

7(z+9)-(27+3z)=0

We add all the numbers together, and all the variables

7(z+9)-(3z+27)=0

We multiply parentheses

7z-(3z+27)+63=0

We get rid of parentheses

7z-3z-27+63=0

We add all the numbers together, and all the variables

4z+36=0

We move all terms containing z to the left, all other terms to the right

4z=-36

z=-36/4

z=-9

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