7(z-(5z+35)+3)=2(z+8)

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Solution for 7(z-(5z+35)+3)=2(z+8) equation: 



7(z-(5z+35)+3)=2(z+8)

We move all terms to the left:

7(z-(5z+35)+3)-(2(z+8))=0



We calculate terms in parentheses: -(2(z+8)), so:

2(z+8)

We multiply parentheses

2z+16

Back to the equation:

-(2z+16)



We get rid of parentheses

7(z-(5z+35)+3)-2z-16=0

We add all the numbers together, and all the variables

-2z+7(z-(5z+35)+3)-16=0

We move all terms containing z to the left, all other terms to the right

-2z+7(z-(5z+35)+3)=16

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