7(z-(8z+18)+4)=4(z+2)

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Solution for 7(z-(8z+18)+4)=4(z+2) equation: 



7(z-(8z+18)+4)=4(z+2)

We move all terms to the left:

7(z-(8z+18)+4)-(4(z+2))=0



We calculate terms in parentheses: -(4(z+2)), so:

4(z+2)

We multiply parentheses

4z+8

Back to the equation:

-(4z+8)



We get rid of parentheses

7(z-(8z+18)+4)-4z-8=0

We add all the numbers together, and all the variables

-4z+7(z-(8z+18)+4)-8=0

We move all terms containing z to the left, all other terms to the right

-4z+7(z-(8z+18)+4)=8

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