7(z-1)+3=(z+1)-1

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Solution for 7(z-1)+3=(z+1)-1 equation: 



7(z-1)+3=(z+1)-1

We move all terms to the left:

7(z-1)+3-((z+1)-1)=0

We multiply parentheses

7z-((z+1)-1)-7+3=0



We calculate terms in parentheses: -((z+1)-1), so:

(z+1)-1

We get rid of parentheses

z+1-1

We add all the numbers together, and all the variables

z

Back to the equation:

-(z)



We add all the numbers together, and all the variables

6z-4=0

We move all terms containing z to the left, all other terms to the right

6z=4

z=4/6

z=2/3

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