7(z-1)-4z=5(2z+4)

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Solution for 7(z-1)-4z=5(2z+4) equation: 



7(z-1)-4z=5(2z+4)

We move all terms to the left:

7(z-1)-4z-(5(2z+4))=0

We add all the numbers together, and all the variables

-4z+7(z-1)-(5(2z+4))=0

We multiply parentheses

-4z+7z-(5(2z+4))-7=0



We calculate terms in parentheses: -(5(2z+4)), so:

5(2z+4)

We multiply parentheses

10z+20

Back to the equation:

-(10z+20)



We add all the numbers together, and all the variables

3z-(10z+20)-7=0

We get rid of parentheses

3z-10z-20-7=0

We add all the numbers together, and all the variables

-7z-27=0

We move all terms containing z to the left, all other terms to the right

-7z=27

z=27/-7

z=-3+6/7

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