7(z-1)=z-(3-2z)

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Solution for 7(z-1)=z-(3-2z) equation: 



7(z-1)=z-(3-2z)

We move all terms to the left:

7(z-1)-(z-(3-2z))=0

We add all the numbers together, and all the variables

7(z-1)-(z-(-2z+3))=0

We multiply parentheses

7z-(z-(-2z+3))-7=0



We calculate terms in parentheses: -(z-(-2z+3)), so:

z-(-2z+3)

We get rid of parentheses

z+2z-3

We add all the numbers together, and all the variables

3z-3

Back to the equation:

-(3z-3)



We get rid of parentheses

7z-3z+3-7=0

We add all the numbers together, and all the variables

4z-4=0

We move all terms containing z to the left, all other terms to the right

4z=4

z=4/4

z=1

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