7(z-2)+39=3(5-z)

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Solution for 7(z-2)+39=3(5-z) equation:


Simplifying
7(z + -2) + 39 = 3(5 + -1z)

Reorder the terms:
7(-2 + z) + 39 = 3(5 + -1z)
(-2 * 7 + z * 7) + 39 = 3(5 + -1z)
(-14 + 7z) + 39 = 3(5 + -1z)

Reorder the terms:
-14 + 39 + 7z = 3(5 + -1z)

Combine like terms: -14 + 39 = 25
25 + 7z = 3(5 + -1z)
25 + 7z = (5 * 3 + -1z * 3)
25 + 7z = (15 + -3z)

Solving
25 + 7z = 15 + -3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '3z' to each side of the equation.
25 + 7z + 3z = 15 + -3z + 3z

Combine like terms: 7z + 3z = 10z
25 + 10z = 15 + -3z + 3z

Combine like terms: -3z + 3z = 0
25 + 10z = 15 + 0
25 + 10z = 15

Add '-25' to each side of the equation.
25 + -25 + 10z = 15 + -25

Combine like terms: 25 + -25 = 0
0 + 10z = 15 + -25
10z = 15 + -25

Combine like terms: 15 + -25 = -10
10z = -10

Divide each side by '10'.
z = -1

Simplifying
z = -1

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