7(z-2)+3=4(z+1)

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Solution for 7(z-2)+3=4(z+1) equation:


Simplifying
7(z + -2) + 3 = 4(z + 1)

Reorder the terms:
7(-2 + z) + 3 = 4(z + 1)
(-2 * 7 + z * 7) + 3 = 4(z + 1)
(-14 + 7z) + 3 = 4(z + 1)

Reorder the terms:
-14 + 3 + 7z = 4(z + 1)

Combine like terms: -14 + 3 = -11
-11 + 7z = 4(z + 1)

Reorder the terms:
-11 + 7z = 4(1 + z)
-11 + 7z = (1 * 4 + z * 4)
-11 + 7z = (4 + 4z)

Solving
-11 + 7z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-11 + 7z + -4z = 4 + 4z + -4z

Combine like terms: 7z + -4z = 3z
-11 + 3z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-11 + 3z = 4 + 0
-11 + 3z = 4

Add '11' to each side of the equation.
-11 + 11 + 3z = 4 + 11

Combine like terms: -11 + 11 = 0
0 + 3z = 4 + 11
3z = 4 + 11

Combine like terms: 4 + 11 = 15
3z = 15

Divide each side by '3'.
z = 5

Simplifying
z = 5

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