7(z-2)=296+6z

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Solution for 7(z-2)=296+6z equation: 



7(z-2)=296+6z

We move all terms to the left:

7(z-2)-(296+6z)=0

We add all the numbers together, and all the variables

7(z-2)-(6z+296)=0

We multiply parentheses

7z-(6z+296)-14=0

We get rid of parentheses

7z-6z-296-14=0

We add all the numbers together, and all the variables

z-310=0

We move all terms containing z to the left, all other terms to the right

z=310

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