7(z-2)=5(2z+2)

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Solution for 7(z-2)=5(2z+2) equation: 



7(z-2)=5(2z+2)

We move all terms to the left:

7(z-2)-(5(2z+2))=0

We multiply parentheses

7z-(5(2z+2))-14=0



We calculate terms in parentheses: -(5(2z+2)), so:

5(2z+2)

We multiply parentheses

10z+10

Back to the equation:

-(10z+10)



We get rid of parentheses

7z-10z-10-14=0

We add all the numbers together, and all the variables

-3z-24=0

We move all terms containing z to the left, all other terms to the right

-3z=24

z=24/-3

z=-8

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