7(z-3)=+4z-1

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Solution for 7(z-3)=+4z-1 equation: 



7(z-3)=+4z-1

We move all terms to the left:

7(z-3)-(+4z-1)=0

We add all the numbers together, and all the variables

7(z-3)-(4z-1)=0

We multiply parentheses

7z-(4z-1)-21=0

We get rid of parentheses

7z-4z+1-21=0

We add all the numbers together, and all the variables

3z-20=0

We move all terms containing z to the left, all other terms to the right

3z=20

z=20/3

z=6+2/3

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