7(z-4)+4z-2=

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Solution for 7(z-4)+4z-2= equation:


7(z-4)+4z-2=0

We simplify the equation to the form, which is simple to understand
7(z-4)+4z-2=0

Reorder the terms in parentheses
+(+7z-28)+4z-2=0

Remove unnecessary parentheses
+7z-28+4z-2=0

We move all terms containing z to the left and all other terms to the right.
+7z+4z=0+28+2

We simplify left and right side of the equation.
+11z=+30

We divide both sides of the equation by 11 to get z.
z=2.72727272727

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