7(z-4)=3z+21+4z

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Solution for 7(z-4)=3z+21+4z equation: 



7(z-4)=3z+21+4z

We move all terms to the left:

7(z-4)-(3z+21+4z)=0

We add all the numbers together, and all the variables

7(z-4)-(7z+21)=0

We multiply parentheses

7z-(7z+21)-28=0

We get rid of parentheses

7z-7z-21-28=0

We add all the numbers together, and all the variables

-49!=0

There is no solution for this equation

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