7(z-4)=4z+2

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Solution for 7(z-4)=4z+2 equation: 



7(z-4)=4z+2

We move all terms to the left:

7(z-4)-(4z+2)=0

We multiply parentheses

7z-(4z+2)-28=0

We get rid of parentheses

7z-4z-2-28=0

We add all the numbers together, and all the variables

3z-30=0

We move all terms containing z to the left, all other terms to the right

3z=30

z=30/3

z=10

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